Abstract
Let d >= 2 be an integer which is not a square. We show that if (L-n)(n >= 0) is the Lucas sequence and (X-m, Y-m)(m >= 1) is the mth solution of the Pell equation X-2 - dY(2) = +/- 1, then the equation Y-m = L-n has at most two positive integer solutions (m, n) except for d = 2 when it has the three solutions (m, n) = (1, 1), (2, 0), (5, 7).